What is the integral of \sqrt[5]{x} ?

The integral of \sqrt[5]{x} is 5/6 x^{6/5}+C

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integral of \sqrt[5]{x}

\frac{5}{6} x^{\frac{6}{5}} + C

Solution steps

Apply the Power Rule

: \frac{5}{6} x^{\frac{6}{5}}

= \frac{5}{6} x^{\frac{6}{5}}

Add a constant to the solution

= \frac{5}{6} x^{\frac{6}{5}} + C

\frac{\partial}{\partial y} (1 - \frac{3}{y} + x)

f (x) = (x + 1)^{x + 1}

y = sin (9 x) + cos (7 x)

\frac{d}{d x} (2 - 5 x^{2})

\int_{2}^{3} \frac{1}{3 x - 2} d x

What is the integral of \sqrt[5]{x} ?
The integral of \sqrt[5]{x} is 5/6 x^{6/5}+C