What is the solution for (x^3+e^y)dy=3x^2dx ?

The solution for (x^3+e^y)dy=3x^2dx is y=\W((x^3)/(e^{c_{1)}})+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^3+e^y)dy=3x^2dx

(x^{3} + e^{y}) d y = 3 x^{2} d x

y = W (\frac{x ^{3}}{e ^{c_{1}}}) + c_{1}

Solution steps

(x^{3} + e^{y}) d y = 3 x^{2} d x

Solve exact ODE:

y = W (\frac{x ^{3}}{e ^{c_{1}}}) + c_{1}

y = W (\frac{x ^{3}}{e ^{c_{1}}}) + c_{1}

y^{^{'}} + 8 y = x e^{- 8 x}

64 - x^{2}

h \to 0 lim (- \frac{1}{x ( x + h )})

\frac{\partial}{\partial x} (e x^{3} - y^{5})

f (x) = x^{e^{x}}

What is the solution for (x^3+e^y)dy=3x^2dx ?
The solution for (x^3+e^y)dy=3x^2dx is y=\W((x^3)/(e^{c_{1)}})+c_{1}