What is the limit as h approaches 0 of-1/(x(x+h)) ?

The limit as h approaches 0 of-1/(x(x+h)) is -1/(x^2)

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limit as h approaches 0 of-1/(x(x+h))

h \to 0 lim (- \frac{1}{x ( x + h )})

- \frac{1}{x ^{2}}

Solution steps

h \to 0 lim (- \frac{1}{x ( x + h )})

Plug in the value

h = 0

= - \frac{1}{x ( x + 0 )}

x (x + 0) = x^{2}

= - \frac{1}{x ^{2}}

\frac{\partial}{\partial x} (e x^{3} - y^{5})

f (x) = x^{e^{x}}

\frac{d}{d x} (4^{2 x})

f (x) = \frac{8 x ^{2} + 8 x + 2}{x}

\frac{( s )}{( s - 1 ) ^{2}}

What is the limit as h approaches 0 of-1/(x(x+h)) ?
The limit as h approaches 0 of-1/(x(x+h)) is -1/(x^2)