What is the integral of (2x^5-7x^3+8) ?

The integral of (2x^5-7x^3+8) is (x^6)/3-(7x^4)/4+8x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x^5-7x^3+8)

\int (2 x^{5} - 7 x^{3} + 8) d x

\frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 8 x + C

Solution steps

\int 2 x^{5} - 7 x^{3} + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{5} d x - \int 7 x^{3} d x + \int 8 d x

\int 2 x^{5} d x = \frac{x ^{6}}{3}

\int 7 x^{3} d x = \frac{7 x ^{4}}{4}

\int 8 d x = 8 x

= \frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 8 x

Add a constant to the solution

= \frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 8 x + C

\frac{\partial}{\partial x} (sin (0.5 x))

\int 20 - 2 x d x

\int i (t) d t

\frac{\partial}{\partial x} (- \frac{x}{x ^{2} - y ^{2}})

\frac{d}{d x} ((2 x)^{x})

What is the integral of (2x^5-7x^3+8) ?
The integral of (2x^5-7x^3+8) is (x^6)/3-(7x^4)/4+8x+C