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Popular >

integral of i(t)

Solution

\int i (t) d t

Solution

\frac{i t ^{2}}{2} + C

Solution steps

\int i t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= i \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= i \frac{t ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{i t ^{2}}{2}

Add a constant to the solution

= \frac{i t ^{2}}{2} + C

Popular Examples

(\partial)/(\partial x)(-x/(sqrt(x^2-y^2)))

\frac{\partial}{\partial x} (- \frac{x}{x ^{2} - y ^{2}})

derivative of (2x^x)

\frac{d}{d x} ((2 x)^{x})

integral of (\sqrt[3]{x^5}-x)(x+2)

y^{^{'''}} - 8 y = 0

derivative of ln(2-5x)

\frac{d}{d x} (ln (2 - 5 x))

Frequently Asked Questions (FAQ)

What is the integral of i(t) ?
The integral of i(t) is (it^2)/2+C