What is the derivative of ln(2-5x) ?

The derivative of ln(2-5x) is -5/(2-5x)

What is the first derivative of ln(2-5x) ?

The first derivative of ln(2-5x) is -5/(2-5x)

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\frac{d}{d x} (ln (2 - 5 x))

- \frac{5}{2 - 5 x}

Solution steps

\frac{d}{d x} (ln (2 - 5 x))

Apply the chain rule:

\frac{1}{2 - 5 x} \frac{d}{d x} (2 - 5 x)

= \frac{1}{2 - 5 x} \frac{d}{d x} (2 - 5 x)

\frac{d}{d x} (2 - 5 x) = - 5

= \frac{1}{2 - 5 x} (- 5)

Simplify

\frac{1}{2 - 5 x} (- 5) : - \frac{5}{2 - 5 x}

= - \frac{5}{2 - 5 x}

\frac{d}{d x} (arctan (x) - x^{2})

\int sin (7 x) ln (sin (7 x)) d x

y^{^{'}} = 2 (1 + y^{2}) x

\frac{d}{d x} (2 x - 1 - \frac{1}{x})

\int \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

What is the derivative of ln(2-5x) ?
The derivative of ln(2-5x) is -5/(2-5x)
What is the first derivative of ln(2-5x) ?
The first derivative of ln(2-5x) is -5/(2-5x)