What is area y=3x+1,y=13+2x-x^2 ?

The answer to area y=3x+1,y=13+2x-x^2 is 343/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=3x+1,y=13+2x-x^2

area

y = 3 x + 1, y = 13 + 2 x - x^{2}

\frac{343}{6}

Decimal Notation

57.16666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} 3 x + 1 - (13 + 2 x - x^{2}) d x

Solve

\int_{- 4}^{3} 3 x + 1 - (13 + 2 x - x^{2}) d x : \frac{343}{6}

The area is:

= \frac{343}{6}

f (x) = 2 x + 1, at x = 1

\frac{d}{d x} (\frac{2 x + ∣ x ∣}{1 + ∣ x ∣})

\int \frac{9 x ^{2} - 8 x + 20}{x ^{3} + 4 x} d x

\frac{75 x}{x ^{2} + 100}

1 - 2 x

What is area y=3x+1,y=13+2x-x^2 ?
The answer to area y=3x+1,y=13+2x-x^2 is 343/6