What is the sum from n=0 to infinity of (1/3)^{2n} ?

The sum from n=0 to infinity of (1/3)^{2n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (1/3)^{2n}

n = 0 \sum \infty (\frac{1}{3})^{2 n}

converges

Solution steps

n = 0 \sum \infty (\frac{1}{3})^{2 n}

Apply Series Ratio Test:

converges

= converges

\frac{5 x}{4 x ^{2} + 1}

\int \frac{x}{x ^{2} + 2 x + 2} d x

Y (x) = x^{3} - x^{2} - 6 x, Y (x) = 0

f (x) = 7 x

\int e^{- 0.8 x} d x

What is the sum from n=0 to infinity of (1/3)^{2n} ?
The sum from n=0 to infinity of (1/3)^{2n} is converges