What is area Y(x)=x^3-x^2-6x,Y(x)=0 ?

The answer to area Y(x)=x^3-x^2-6x,Y(x)=0 is 253/12

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area Y(x)=x^3-x^2-6x,Y(x)=0

area

Y (x) = x^{3} - x^{2} - 6 x, Y (x) = 0

\frac{253}{12}

Decimal Notation

21.08333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{3} - x^{2} - 6 x d x

Solve

\int_{- 2}^{3} x^{3} - x^{2} - 6 x d x : \frac{253}{12}

The area is:

= \frac{253}{12}

f (x) = 7 x

\int e^{- 0.8 x} d x

\frac{\partial}{\partial x} (x^{2} \cdot ln (y))

\frac{d}{d x} (sin (2 x - \frac{π}{3}))

\frac{\partial}{\partial x} (x^{3} + y^{2} - y x^{2} - x y)

What is area Y(x)=x^3-x^2-6x,Y(x)=0 ?
The answer to area Y(x)=x^3-x^2-6x,Y(x)=0 is 253/12