What is the derivative of (x^2+4)^3 ?

The derivative of (x^2+4)^3 is 6x(x^2+4)^2

What is the first derivative of (x^2+4)^3 ?

The first derivative of (x^2+4)^3 is 6x(x^2+4)^2

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derivative of

(x^{2} + 4)^{3}

6 x (x^{2} + 4)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 4)^{3})

Apply the chain rule:

3 (x^{2} + 4)^{2} \frac{d}{d x} (x^{2} + 4)

= 3 (x^{2} + 4)^{2} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= 3 (x^{2} + 4)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 4)^{2}

\int (θ^{6} + sec^{2} (θ)) d θ

28 - x^{2}

\int \frac{y}{3 + x y} d x

\int \frac{1}{( 3 x + 2 ) ^{3}} d x

(- 4 x^{2} + 16)^{2}

What is the derivative of (x^2+4)^3 ?
The derivative of (x^2+4)^3 is 6x(x^2+4)^2
What is the first derivative of (x^2+4)^3 ?
The first derivative of (x^2+4)^3 is 6x(x^2+4)^2