What is the derivative of (-4x^2+16)^2 ?

The derivative of (-4x^2+16)^2 is -16x(-4x^2+16)

What is the first derivative of (-4x^2+16)^2 ?

The first derivative of (-4x^2+16)^2 is -16x(-4x^2+16)

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derivative of

(- 4 x^{2} + 16)^{2}

- 16 x (- 4 x^{2} + 16)

Solution steps

\frac{d}{d x} ((- 4 x^{2} + 16)^{2})

Apply the chain rule:

2 (- 4 x^{2} + 16) \frac{d}{d x} (- 4 x^{2} + 16)

= 2 (- 4 x^{2} + 16) \frac{d}{d x} (- 4 x^{2} + 16)

\frac{d}{d x} (- 4 x^{2} + 16) = - 8 x

= 2 (- 4 x^{2} + 16) (- 8 x)

Simplify

= - 16 x (- 4 x^{2} + 16)

n = 1 \sum \infty (- \frac{3}{4})^{n - 1}

\int_{0}^{1} 8 x d x

n = 0 \sum \infty \frac{n !}{2 n !}

3 (1 + e^{- 0.4 t})

y = 5 x - 2 x, (1, 3)

What is the derivative of (-4x^2+16)^2 ?
The derivative of (-4x^2+16)^2 is -16x(-4x^2+16)
What is the first derivative of (-4x^2+16)^2 ?
The first derivative of (-4x^2+16)^2 is -16x(-4x^2+16)