What is the integral from 0 to 1 of 8x ?

The integral from 0 to 1 of 8x is 4

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integral from 0 to 1 of 8x

\int_{0}^{1} 8 x d x

4

Solution steps

\int_{0}^{1} 8 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= 8 [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 8 \cdot \frac{1}{2}

Simplify

= 4

n = 0 \sum \infty \frac{n !}{2 n !}

3 (1 + e^{- 0.4 t})

y = 5 x - 2 x, (1, 3)

x \to 0 lim (sin (x) - 2 x)

\int 8 x y