What is inverse oflaplace (0.6)/(s+10) ?

The answer to inverse oflaplace (0.6)/(s+10) is 0.6e^{-10t}

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inverse oflaplace (0.6)/(s+10)

inverse laplace

\frac{0.6}{s + 10}

0.6 e^{- 10 t}

Solution steps

L^{- 1} {\frac{0.6}{s + 10}}

= L^{- 1} {0.6 \cdot \frac{1}{s + 10}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 0.6 L^{- 1} {\frac{1}{s + 10}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 10}} = e^{- 10 t}

= 0.6 e^{- 10 t}

\int \frac{e ^{x} - 3}{x} d x

x \to 1 lim (2 x^{2} - 3 x + 4)

\frac{d}{d x} (x^{\frac{1}{11}})

y = - 3 cos (x), at x = \frac{3}{4} π

f (x) = \frac{e ^{- 2 x}}{x}

What is inverse oflaplace (0.6)/(s+10) ?
The answer to inverse oflaplace (0.6)/(s+10) is 0.6e^{-10t}