What is the tangent of y=-3cos(x),\at x= 3/4 pi ?

The tangent of y=-3cos(x),\at x= 3/4 pi is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))

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tangent of y=-3cos(x),\at x= 3/4 pi

tangent of

y = - 3 cos (x), at x = \frac{3}{4} π

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

Compute the slope of

y = - 3 cos (x)

x = \frac{3}{4} π : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{3}{4} π, \frac{3}{2}) : y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

f (x) = \frac{e ^{- 2 x}}{x}

\frac{d}{d x} (\frac{2 ( x ^{2} + 3 )}{3 x})

\frac{d}{d x} (\frac{2 x ^{\frac{3}{2}}}{x})

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

\int \frac{sin ( 2 x )}{( 1 + cos ( 2 x ) ) ^{3}} d x

What is the tangent of y=-3cos(x),\at x= 3/4 pi ?
The tangent of y=-3cos(x),\at x= 3/4 pi is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))