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Popular >

derivative of sin(-1(4x+1))

Solution

derivative of

sin (- 1 (4 x + 1))

Solution

- cos (1 + 4 x) \cdot 4

Solution steps

\frac{d}{d x} (sin (- 1 \cdot (4 x + 1)))

Simplify

sin (- 1 \cdot (4 x + 1)) : - sin (1 + 4 x)

= \frac{d}{d x} (- sin (1 + 4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (1 + 4 x))

Apply the chain rule:

cos (1 + 4 x) \frac{d}{d x} (1 + 4 x)

= cos (1 + 4 x) \frac{d}{d x} (1 + 4 x)

\frac{d}{d x} (1 + 4 x) = 4

= - cos (1 + 4 x) \cdot 4

Popular Examples

integral from 0 to pi/2 of sin^2(t)

\int_{0}^{\frac{π}{2}} sin^{2} (t) d t

derivative of x^9ln(8x)

\frac{d}{d x} (x^{9} ln (8 x))

derivative of ln((4x^4sin(-7x)/(3x-3)))

\frac{d}{d x} (ln (\frac{4 x ^{4} sin ( - 7 x )}{3 x - 3}))

derivative of 2/(x^3+c)

\frac{d}{d x} (\frac{2}{x ^{3}} + c)

integral from 3 to 6 of 1/((4-x)^2)

\int_{3}^{6} \frac{1}{( 4 - x ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the derivative of sin(-1(4x+1)) ?
The derivative of sin(-1(4x+1)) is -cos(1+4x)*4
What is the first derivative of sin(-1(4x+1)) ?
The first derivative of sin(-1(4x+1)) is -cos(1+4x)*4