What is (\partial)/(\partial x)(cos(y-x)) ?

The answer to (\partial)/(\partial x)(cos(y-x)) is sin(y-x)

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(\partial)/(\partial x)(cos(y-x))

\frac{\partial}{\partial x} (cos (y - x))

sin (y - x)

Solution steps

\frac{\partial}{\partial x} (cos (y - x))

Treat

y

as a constant

Apply the chain rule:

- sin (y - x) \frac{\partial}{\partial x} (y - x)

= - sin (y - x) \frac{\partial}{\partial x} (y - x)

\frac{\partial}{\partial x} (y - x) = - 1

= - sin (y - x) (- 1)

Simplify

= sin (y - x)

x \to - 2 lim (7 x + 12)

\int \frac{ln ( 17 x )}{x} d x

\frac{\partial}{\partial x} ((\frac{x}{2})^{2})

\int_{0}^{1} ln (x) d x

\frac{d}{d x} (\frac{2 x}{7 - tan ( x )})

What is (\partial)/(\partial x)(cos(y-x)) ?
The answer to (\partial)/(\partial x)(cos(y-x)) is sin(y-x)