What is the integral from 0 to 0.6 of (600x) ?

The integral from 0 to 0.6 of (600x) is 108

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integral from 0 to 0.6 of (600x)

\int_{0}^{0.6} (600 x) d x

108

Solution steps

\int_{0}^{0.6} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 600 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 600 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 600 \cdot 0.18

Simplify

= 108

\frac{d y}{d x} = \frac{( sec ( y ) )}{( x - 1 ) ^{2}}

\int_{0}^{π} sin^{5} (x) d x

\frac{s}{( s + 1 )}

\frac{\partial}{\partial z} (x^{yz})

What is the integral from 0 to 0.6 of (600x) ?
The integral from 0 to 0.6 of (600x) is 108