What is the derivative of f(x)=-3e^{x+1} ?

The derivative of f(x)=-3e^{x+1} is -3e^{x+1}

What is the first derivative of f(x)=-3e^{x+1} ?

The first derivative of f(x)=-3e^{x+1} is -3e^{x+1}

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derivative of

f (x) = - 3 e^{x + 1}

- 3 e^{x + 1}

Solution steps

\frac{d}{d x} (- 3 e^{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (e^{x + 1})

Apply the chain rule:

e^{x + 1} \frac{d}{d x} (x + 1)

= e^{x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - 3 e^{x + 1} \cdot 1

Simplify

= - 3 e^{x + 1}

f (x) = 8 x - x^{2}

x \to 0 + lim (\frac{1}{x + 1})

\frac{\partial}{\partial x} (1 - x^{2} - y^{2})

x \to 1 lim (x - x)

\frac{\partial}{\partial x} (4 x^{- 1})

What is the derivative of f(x)=-3e^{x+1} ?
The derivative of f(x)=-3e^{x+1} is -3e^{x+1}
What is the first derivative of f(x)=-3e^{x+1} ?
The first derivative of f(x)=-3e^{x+1} is -3e^{x+1}