What is (\partial)/(\partial x)(4x^{-1}) ?

The answer to (\partial)/(\partial x)(4x^{-1}) is -4/(x^2)

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(\partial)/(\partial x)(4x^{-1})

\frac{\partial}{\partial x} (4 x^{- 1})

- \frac{4}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (4 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 1 \cdot x^{- 1 - 1})

Simplify

4 (- 1 \cdot x^{- 1 - 1}) : - \frac{4}{x ^{2}}

= - \frac{4}{x ^{2}}

f (x) = x^{2} + 6 x, at a = 3

x \to 2 lim (3 x - 2)

\frac{x ^{2}}{8 + x}

\int_{0}^{1} 23 cos (x^{2}) d x

\frac{d}{d x} ((tan (x))^{\frac{1}{x}})

What is (\partial)/(\partial x)(4x^{-1}) ?
The answer to (\partial)/(\partial x)(4x^{-1}) is -4/(x^2)