What is the derivative of f(x)=cos(tan(x)) ?

The derivative of f(x)=cos(tan(x)) is -sin(tan(x))sec^2(x)

What is the first derivative of f(x)=cos(tan(x)) ?

The first derivative of f(x)=cos(tan(x)) is -sin(tan(x))sec^2(x)

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derivative of

f (x) = cos (tan (x))

- sin (tan (x)) sec^{2} (x)

Solution steps

\frac{d}{d x} (cos (tan (x)))

Apply the chain rule:

- sin (tan (x)) \frac{d}{d x} (tan (x))

= - sin (tan (x)) \frac{d}{d x} (tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= - sin (tan (x)) sec^{2} (x)

y^{^{''}} + a y^{^{'}} + b y = t + e^{3 t}

x \to - 1 lim (ln (x + 1))

\frac{\partial}{\partial x} (\frac{1}{2} (x^{2} + 4 y^{2}))

\frac{\partial}{\partial x} (\frac{1}{2 x})

2 x y \frac{d y}{d x} = y^{2} - x^{2} + 1

What is the derivative of f(x)=cos(tan(x)) ?
The derivative of f(x)=cos(tan(x)) is -sin(tan(x))sec^2(x)
What is the first derivative of f(x)=cos(tan(x)) ?
The first derivative of f(x)=cos(tan(x)) is -sin(tan(x))sec^2(x)