What is the tangent of f(x)=(6x)/(x-1),(-1,3) ?

The tangent of f(x)=(6x)/(x-1),(-1,3) is y=-3/2 x+3/2

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tangent of f(x)=(6x)/(x-1),(-1,3)

tangent of

f (x) = \frac{6 x}{x - 1}, (- 1, 3)

y = - \frac{3}{2} x + \frac{3}{2}

Solution steps

Find the slope of

f (x) = \frac{6 x}{x - 1} : \frac{df ( x )}{d x} = - \frac{6}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{6 x}{x - 1}

(- 1, 3) : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- 1, 3) : y = - \frac{3}{2} x + \frac{3}{2}

y = - \frac{3}{2} x + \frac{3}{2}

\int \frac{( 2 x ^{3} + 3 x )}{x ^{4} + 3 x ^{2} + 7} d x

\frac{\partial}{\partial x} (4 x cos (4 x y))

x \to 0 lim (\frac{sin ( 20 x )}{x})

x \to 2 + lim (- \frac{1}{x ^{2} - 4})

\int (tan (θ) sec (θ)) d θ

What is the tangent of f(x)=(6x)/(x-1),(-1,3) ?
The tangent of f(x)=(6x)/(x-1),(-1,3) is y=-3/2 x+3/2