What is the derivative of f(x)=6x^2+x-3 ?

The derivative of f(x)=6x^2+x-3 is 12x+1

What is the first derivative of f(x)=6x^2+x-3 ?

The first derivative of f(x)=6x^2+x-3 is 12x+1

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derivative of

f (x) = 6 x^{2} + x - 3

12 x + 1

Solution steps

\frac{d}{d x} (6 x^{2} + x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 12 x + 1 - 0

Simplify

= 12 x + 1

\frac{t}{2}

y = x, x = 9, y = 0

x y^{^{'}} + 2 y = 8 x^{2}

3 y^{^{''}} + 5 y^{^{'}} + 2 y = 0

\int (3 + 2 cos (x))^{2} d x

What is the derivative of f(x)=6x^2+x-3 ?
The derivative of f(x)=6x^2+x-3 is 12x+1
What is the first derivative of f(x)=6x^2+x-3 ?
The first derivative of f(x)=6x^2+x-3 is 12x+1