What is (\partial)/(\partial y)(10-6y+e^{-3x}) ?

The answer to (\partial)/(\partial y)(10-6y+e^{-3x}) is -6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(10-6y+e^{-3x})

\frac{\partial}{\partial y} (10 - 6 y + e^{- 3 x})

- 6

Solution steps

\frac{\partial}{\partial y} (10 - 6 y + e^{- 3 x})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (10) - \frac{\partial}{\partial y} (6 y) + \frac{\partial}{\partial y} (e^{- 3 x})

\frac{\partial}{\partial y} (10) = 0

\frac{\partial}{\partial y} (6 y) = 6

\frac{\partial}{\partial y} (e^{- 3 x}) = 0

= 0 - 6 + 0

Simplify

= - 6

\frac{d}{d t} (3 e^{t})

F (x) = \frac{x ^{2}}{4 + x}

\frac{d y}{d x} = y + y^{3}

\int_{- 9}^{4} ∣ x + 5 ∣ d x

\int \frac{x}{x ^{2} - 6 x + 8} d x

What is (\partial)/(\partial y)(10-6y+e^{-3x}) ?
The answer to (\partial)/(\partial y)(10-6y+e^{-3x}) is -6