What is the derivative of 1/(sqrt(t)) ?

The derivative of 1/(sqrt(t)) is -1/(2t^{3/2)}

What is the first derivative of 1/(sqrt(t)) ?

The first derivative of 1/(sqrt(t)) is -1/(2t^{3/2)}

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derivative of

\frac{1}{t}

- \frac{1}{2 t ^{\frac{3}{2}}}

Solution steps

\frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{2} t^{- \frac{1}{2} - 1}

Simplify

- \frac{1}{2} t^{- \frac{1}{2} - 1} : - \frac{1}{2 t ^{\frac{3}{2}}}

= - \frac{1}{2 t ^{\frac{3}{2}}}

\int_{- 1}^{2} (x + 2 - x^{2}) d x

\frac{d}{d x} (\frac{9}{e ^{x} + e ^{- x}})

1 + x^{2}

\int \frac{x ^{2}}{1 - 2 x ^{2}} d x

\frac{\partial}{\partial x} (ln (3 x^{2} + 4 y^{2} + 2))

What is the derivative of 1/(sqrt(t)) ?
The derivative of 1/(sqrt(t)) is -1/(2t^{3/2)}
What is the first derivative of 1/(sqrt(t)) ?
The first derivative of 1/(sqrt(t)) is -1/(2t^{3/2)}