What is the derivative of 2/(sqrt(x+1)) ?

The derivative of 2/(sqrt(x+1)) is -1/((x+1)^{3/2)}

What is the first derivative of 2/(sqrt(x+1)) ?

The first derivative of 2/(sqrt(x+1)) is -1/((x+1)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2}{x + 1})

- \frac{1}{( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{2}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x + 1)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 1)

= - \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 (- \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

2 (- \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{1}{( x + 1 ) ^{\frac{3}{2}}}

= - \frac{1}{( x + 1 ) ^{\frac{3}{2}}}

\int \frac{2 x}{1 - x ^{4}} d x

(- 2.9) (- 1.7)

f (x) = 4 sin (x), at x = \frac{π}{4}

\frac{d}{d x} (3 x^{2} - 2 x + 2)

\frac{d}{d x} (sin^{x} (x))

What is the derivative of 2/(sqrt(x+1)) ?
The derivative of 2/(sqrt(x+1)) is -1/((x+1)^{3/2)}
What is the first derivative of 2/(sqrt(x+1)) ?
The first derivative of 2/(sqrt(x+1)) is -1/((x+1)^{3/2)}