What is the derivative of 3x^2-2x+2 ?

The derivative of 3x^2-2x+2 is 6x-2

What is the first derivative of 3x^2-2x+2 ?

The first derivative of 3x^2-2x+2 is 6x-2

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\frac{d}{d x} (3 x^{2} - 2 x + 2)

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 6 x - 2 + 0

Simplify

= 6 x - 2

\frac{d}{d x} (sin^{x} (x))

f (x) = 5 x - 9 x^{2}, at x = 1

\frac{d}{d x} (- 8 cos (x))

e^{x} x + 2 e^{x}

\int \frac{8 + x}{64 - x ^{2}} d x

What is the derivative of 3x^2-2x+2 ?
The derivative of 3x^2-2x+2 is 6x-2
What is the first derivative of 3x^2-2x+2 ?
The first derivative of 3x^2-2x+2 is 6x-2