What is the derivative of y=(x^2-3)^5 ?

The derivative of y=(x^2-3)^5 is 10x(x^2-3)^4

What is the first derivative of y=(x^2-3)^5 ?

The first derivative of y=(x^2-3)^5 is 10x(x^2-3)^4

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derivative of

y = (x^{2} - 3)^{5}

10 x (x^{2} - 3)^{4}

Solution steps

\frac{d}{d x} ((x^{2} - 3)^{5})

Apply the chain rule:

5 (x^{2} - 3)^{4} \frac{d}{d x} (x^{2} - 3)

= 5 (x^{2} - 3)^{4} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= 5 (x^{2} - 3)^{4} \cdot 2 x

Simplify

= 10 x (x^{2} - 3)^{4}

y = e^{p} (p + p p)

x \to 8 - lim (\frac{1}{( x - 8 ) ^{2}})

\int (cos (x^{2})) d x

\int x e^{2 x + 1} d x

x \to 0 lim (\frac{x}{x ^{2} - 6 x})

What is the derivative of y=(x^2-3)^5 ?
The derivative of y=(x^2-3)^5 is 10x(x^2-3)^4
What is the first derivative of y=(x^2-3)^5 ?
The first derivative of y=(x^2-3)^5 is 10x(x^2-3)^4