What is the derivative of y=cos(a^8+x^8) ?

The derivative of y=cos(a^8+x^8) is -sin(a^8+x^8)*8x^7

What is the first derivative of y=cos(a^8+x^8) ?

The first derivative of y=cos(a^8+x^8) is -sin(a^8+x^8)*8x^7

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derivative of

y = cos (a^{8} + x^{8})

- sin (a^{8} + x^{8}) \cdot 8 x^{7}

Solution steps

\frac{d}{d x} (cos (a^{8} + x^{8}))

Apply the chain rule:

- sin (a^{8} + x^{8}) \frac{d}{d x} (a^{8} + x^{8})

= - sin (a^{8} + x^{8}) \frac{d}{d x} (a^{8} + x^{8})

\frac{d}{d x} (a^{8} + x^{8}) = 8 x^{7}

= - sin (a^{8} + x^{8}) \cdot 8 x^{7}

\frac{d}{d x} (2 csc^{2} (x) cot (x))

\frac{d}{d x} (\frac{4 x ^{\frac{2}{3}}}{x ^{2} + 1})

\int \frac{1}{( x + 1 ) x ^{2} + 2 x - 15} d x

x \to 3 + lim (\frac{2}{x ^{2} - 9})

\frac{e ^{x}}{5 x ^{6}}

What is the derivative of y=cos(a^8+x^8) ?
The derivative of y=cos(a^8+x^8) is -sin(a^8+x^8)*8x^7
What is the first derivative of y=cos(a^8+x^8) ?
The first derivative of y=cos(a^8+x^8) is -sin(a^8+x^8)*8x^7