What is the derivative of f(x)=x^3+2x ?

The derivative of f(x)=x^3+2x is 3x^2+2

What is the first derivative of f(x)=x^3+2x ?

The first derivative of f(x)=x^3+2x is 3x^2+2

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derivative of

f (x) = x^{3} + 2 x

3 x^{2} + 2

Solution steps

\frac{d}{d x} (x^{3} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

= 3 x^{2} + 2

2 x^{3} + 4 x^{2} - x + 2

y = \frac{x - 4}{x}

x \to - 10 lim (f (x))

x \to 3 - lim (\frac{x + 3}{x ^{2} - 9})

\int \frac{4}{e ^{t}} d t

What is the derivative of f(x)=x^3+2x ?
The derivative of f(x)=x^3+2x is 3x^2+2
What is the first derivative of f(x)=x^3+2x ?
The first derivative of f(x)=x^3+2x is 3x^2+2