What is the solution for (dy)/(dx)+3/x y=16y^3,y(1)=1 ?

The solution for (dy)/(dx)+3/x y=16y^3,y(1)=1 is y=sqrt(5/(x(32-27x^5)))

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(dy)/(dx)+3/x y=16y^3,y(1)=1

\frac{d y}{d x} + \frac{3}{x} y = 16 y^{3}, y (1) = 1

y = \frac{5}{x ( 32 - 27 x ^{5} )}

Solution steps

\frac{d y}{d x} + \frac{3}{x} y = 16 y^{3}

Solve Bernoulli ODE:

y = \frac{5}{x ( 32 - 27 x ^{5} )}

y = \frac{5}{x ( 32 - 27 x ^{5} )}

\int_{- 2}^{2} 2 - 4 - x^{2} d x

\frac{1}{s + 5}

f (x) = - 5 x^{2}, at x = 8

x (x + 1) (\frac{d y}{d x}) + x y = 1, y (e) = 1

\int \frac{1}{9 x - 7} d x

What is the solution for (dy)/(dx)+3/x y=16y^3,y(1)=1 ?
The solution for (dy)/(dx)+3/x y=16y^3,y(1)=1 is y=sqrt(5/(x(32-27x^5)))