What is the derivative of y=x^2ln(x^2) ?

The derivative of y=x^2ln(x^2) is 2xln(x^2)+2x

What is the first derivative of y=x^2ln(x^2) ?

The first derivative of y=x^2ln(x^2) is 2xln(x^2)+2x

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derivative of

y = x^{2} ln (x^{2})

2 x ln (x^{2}) + 2 x

Solution steps

\frac{d}{d x} (x^{2} ln (x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = ln (x^{2})

= \frac{d}{d x} (x^{2}) ln (x^{2}) + \frac{d}{d x} (ln (x^{2})) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 2 x ln (x^{2}) + \frac{2}{x} x^{2}

\frac{2}{x} x^{2} = 2 x

= 2 x ln (x^{2}) + 2 x

\frac{d}{d x} (1 + x + 1)

ln (x + 3)

\int \frac{e ^{\frac{2}{x}}}{x ^{2}} d x

y^{^{'}} + 6 y = 4 x^{3} e^{- 6 x}

\frac{d y}{d x} = 5 + e^{y - 5 x + 1}, y (0) = - 1

What is the derivative of y=x^2ln(x^2) ?
The derivative of y=x^2ln(x^2) is 2xln(x^2)+2x
What is the first derivative of y=x^2ln(x^2) ?
The first derivative of y=x^2ln(x^2) is 2xln(x^2)+2x