What is the integral of 8cos(θ) ?

The integral of 8cos(θ) is 8sin(θ)+C

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integral of 8cos(θ)

\int 8 cos (θ) d θ

8 sin (θ) + C

Solution steps

\int 8 cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= 8 sin (θ)

Add a constant to the solution

= 8 sin (θ) + C

y = cos (x), y = sin (2 x), x = 0, x = \frac{π}{2}

\int tan^{4} (3 x) d x

\frac{\partial}{\partial x} (ln (x yz))

f (x) = \frac{3}{4 x + 7}

\frac{d}{d x} (\frac{2 x - 5}{x + 1})