What is the derivative of (x^4/2-3x^2+10) ?

The derivative of (x^4/2-3x^2+10) is 2x^3-6x

What is the first derivative of (x^4/2-3x^2+10) ?

The first derivative of (x^4/2-3x^2+10) is 2x^3-6x

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\frac{d}{d x} (\frac{x ^{4}}{2} - 3 x^{2} + 10)

2 x^{3} - 6 x

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{2} - 3 x^{2} + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{2}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (10)

\frac{d}{d x} (\frac{x ^{4}}{2}) = 2 x^{3}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (10) = 0

= 2 x^{3} - 6 x + 0

Simplify

= 2 x^{3} - 6 x

\int \frac{y ^{3} e ^{y^{2}}}{( y ^{2} + 1 ) ^{2}} d y

f (x) = x^{2} - 2 x, (0, 2)

y^{^{''}} - 8 y^{^{'}} + 15 y = 4 e^{t}

\int \frac{x}{( 1 + x ^{2} ) ^{2}} d x

What is the derivative of (x^4/2-3x^2+10) ?
The derivative of (x^4/2-3x^2+10) is 2x^3-6x
What is the first derivative of (x^4/2-3x^2+10) ?
The first derivative of (x^4/2-3x^2+10) is 2x^3-6x