What is the derivative of sqrt(3-3x^2) ?

The derivative of sqrt(3-3x^2) is -(3x)/(sqrt(3-3x^2))

What is the first derivative of sqrt(3-3x^2) ?

The first derivative of sqrt(3-3x^2) is -(3x)/(sqrt(3-3x^2))

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\frac{d}{d x} (3 - 3 x^{2})

- \frac{3 x}{3 - 3 x ^{2}}

Solution steps

\frac{d}{d x} (3 - 3 x^{2})

Apply the chain rule:

\frac{1}{2 3 - 3 x ^{2}} \frac{d}{d x} (3 - 3 x^{2})

= \frac{1}{2 3 - 3 x ^{2}} \frac{d}{d x} (3 - 3 x^{2})

\frac{d}{d x} (3 - 3 x^{2}) = - 6 x

= \frac{1}{2 3 - 3 x ^{2}} (- 6 x)

Simplify

\frac{1}{2 3 - 3 x ^{2}} (- 6 x) : - \frac{3 x}{3 - 3 x ^{2}}

= - \frac{3 x}{3 - 3 x ^{2}}

\frac{s + 4}{( s + 1 ) ^{2}}

\int \frac{1}{x} - \frac{2}{x ^{2} + 1} d x

\frac{( - 2 )}{( 6 s + s ^{2} )}

y d x = 2 (x + y) d y

(x + y) d x + (x + 2 y) d y = 0, y (2) = 3

What is the derivative of sqrt(3-3x^2) ?
The derivative of sqrt(3-3x^2) is -(3x)/(sqrt(3-3x^2))
What is the first derivative of sqrt(3-3x^2) ?
The first derivative of sqrt(3-3x^2) is -(3x)/(sqrt(3-3x^2))