What is the solution for 2(dy)/(dt)-y=4sin(3t) ?

The solution for 2(dy)/(dt)-y=4sin(3t) is y=-(4(6cos(3t)+sin(3t)))/(37)+c_{1}e^{1/2 t}

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2(dy)/(dt)-y=4sin(3t)

2 \frac{d y}{d t} - y = 4 sin (3 t)

y = - \frac{4 ( 6 cos ( 3 t ) + sin ( 3 t ) )}{37} + c_{1} e^{\frac{1}{2} t}

Solution steps

2 \frac{d y}{d t} - y = 4 sin (3 t)

Solve linear ODE:

y = - \frac{4 ( 6 cos ( 3 t ) + sin ( 3 t ) )}{37} + c_{1} e^{\frac{1}{2} t}

y = - \frac{4 ( 6 cos ( 3 t ) + sin ( 3 t ) )}{37} + c_{1} e^{\frac{1}{2} t}

f (x) = x^{2} + 7, (1, 8)

\int 2 sin (x) - 3 sec (x) tan (x) d x

\int \frac{t ^{5}}{( t ^{2} + 4 ) ^{2}} d t

\frac{d}{d x} (ln (arccos (x)))

2 y^{^{''}} + 5 y^{^{'}} - 18 y = 0

What is the solution for 2(dy)/(dt)-y=4sin(3t) ?
The solution for 2(dy)/(dt)-y=4sin(3t) is y=-(4(6cos(3t)+sin(3t)))/(37)+c_{1}e^{1/2 t}