What is the d/(dn)((1+i)^n) ?

The d/(dn)((1+i)^n) is (1+i)^nln(1+i)

What is the first d/(dn)((1+i)^n) ?

The first d/(dn)((1+i)^n) is (1+i)^nln(1+i)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d n} ((1 + i)^{n})

(1 + i)^{n} ln (1 + i)

Solution steps

\frac{d}{d n} ((1 + i)^{n})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= (1 + i)^{n} ln (1 + i)

f (x) = - \frac{3}{x ^{4}}

\int 0.3 x^{2} d x

\int - 4 ln (x) d x

\frac{\partial}{\partial x} (4 (x - y) \cdot e^{4 y + 2 x^{2}})

x \to 2 - lim (tan (\frac{π x}{4}))