What is the integral of-4ln(x) ?

The integral of-4ln(x) is -4(xln(x)-x)+C

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integral of-4ln(x)

\int - 4 ln (x) d x

- 4 (x ln (x) - x) + C

Solution steps

\int - 4 ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int ln (x) d x

Apply Integration By Parts

: x ln (x) - \int 1 d x

= - 4 (x ln (x) - \int 1 d x)

\int 1 d x = x

= - 4 (x ln (x) - x)

Add a constant to the solution

= - 4 (x ln (x) - x) + C

\frac{\partial}{\partial x} (4 (x - y) \cdot e^{4 y + 2 x^{2}})

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