What is (\partial)/(\partial x)(3sin(xy)) ?

The answer to (\partial)/(\partial x)(3sin(xy)) is 3cos(xy)y

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(\partial)/(\partial x)(3sin(xy))

\frac{\partial}{\partial x} (3 sin (x y))

3 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (3 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 3 cos (x y) y

\frac{d y}{d x} - 2 y = 4

(7 x^{2} - 14 x + 14) e^{x}

\frac{\partial}{\partial y} (y^{2} sin (x))

\frac{d}{d x} (ln (\frac{9 - x ^{2}}{9 + x ^{2}}))

y^{^{'}} = x y - 3 y

What is (\partial)/(\partial x)(3sin(xy)) ?
The answer to (\partial)/(\partial x)(3sin(xy)) is 3cos(xy)y