What is (\partial)/(\partial y)(y^2sin(x)) ?

The answer to (\partial)/(\partial y)(y^2sin(x)) is 2ysin(x)

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(\partial)/(\partial y)(y^2sin(x))

\frac{\partial}{\partial y} (y^{2} sin (x))

2 y sin (x)

Solution steps

\frac{\partial}{\partial y} (y^{2} sin (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sin (x) \cdot 2 y^{2 - 1}

Simplify

= 2 y sin (x)

\frac{d}{d x} (ln (\frac{9 - x ^{2}}{9 + x ^{2}}))

y^{^{'}} = x y - 3 y

x \to 8 lim (x^{\frac{2}{3}})

\frac{d ^{2}}{d y ^{2}} (ln (x^{2} + y^{2}))

\int \frac{1}{cos ^{2} ( 2 x )} d x

What is (\partial)/(\partial y)(y^2sin(x)) ?
The answer to (\partial)/(\partial y)(y^2sin(x)) is 2ysin(x)