What is (d^2)/(dy^2)(ln(sqrt(x^2+y^2))) ?

The answer to (d^2)/(dy^2)(ln(sqrt(x^2+y^2))) is (x^2-y^2)/((x^2+y^2)^2)

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(d^2)/(dy^2)(ln(sqrt(x^2+y^2)))

\frac{d ^{2}}{d y ^{2}} (ln (x^{2} + y^{2}))

\frac{x ^{2} - y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{d ^{2}}{d y ^{2}} (ln (x^{2} + y^{2}))

\frac{d}{d y} (ln (x^{2} + y^{2})) = \frac{y}{x ^{2} + y ^{2}}

= \frac{d}{d y} (\frac{y}{x ^{2} + y ^{2}})

\frac{d}{d y} (\frac{y}{x ^{2} + y ^{2}}) = \frac{x ^{2} - y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{x ^{2} - y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

\int \frac{1}{cos ^{2} ( 2 x )} d x

y^{^{''}} + y^{^{'}} - 2 y = e^{- x}

\frac{\partial}{\partial x} (2^{\frac{1}{x}})

(3, 5), (8, 7)

\int \frac{3 x ^{2} - 6 x ^{2} + x}{x ^{3}} d x

What is (d^2)/(dy^2)(ln(sqrt(x^2+y^2))) ?
The answer to (d^2)/(dy^2)(ln(sqrt(x^2+y^2))) is (x^2-y^2)/((x^2+y^2)^2)