What is the limit as x approaches 0 of (1-e^{-x})/(sin(x)) ?

The limit as x approaches 0 of (1-e^{-x})/(sin(x)) is 1

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limit as x approaches 0 of (1-e^{-x})/(sin(x))

x \to 0 lim (\frac{1 - e ^{- x}}{sin ( x )})

1

Solution steps

x \to 0 lim (\frac{1 - e ^{- x}}{sin ( x )})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{e ^{- x}}{cos ( x )})

= x \to 0 lim (\frac{e ^{- x}}{cos ( x )})

Plug in the value

x = 0

= \frac{e ^{- 0}}{cos ( 0 )}

Simplify

\frac{e ^{- 0}}{cos ( 0 )} : 1

= 1

x (x^{2} + 1) d y = 1 - y^{2} d x

\frac{d}{d x} (500 (1 + \frac{4 x}{50 + x ^{2}}))

\int z^{'} d z

\int \frac{x ^{2}}{x ^{2} - 49} d x

(2 x + 3) + (2 y - 2) \frac{d y}{d x} = 0

What is the limit as x approaches 0 of (1-e^{-x})/(sin(x)) ?
The limit as x approaches 0 of (1-e^{-x})/(sin(x)) is 1