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Popular >

y^'+y/x =2y^2

Solution

y^{^{'}} + \frac{y}{x} = 2 y^{2}

Solution

y = \frac{1}{x ( - 2 ln ( x ) + c _{1} )}

Solution steps

y^{'} (x) + \frac{y}{x} = 2 y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 2 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 2 ln ( x ) + c _{1} )}

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y^'=3-(3x)/(10000)

y^{^{'}} = 3 - \frac{3 x}{10000}

integral of t^2e^{2t}

\int t^{2} e^{2 t} d t

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\int (2 x + 4) e^{2 x + 4} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x =2y^2 ?
The solution for y^'+y/x =2y^2 is y= 1/(x(-2ln(x)+c_{1))}