What is the solution for (dy)/(dx)=((x^2y^2))/(1+x) ?

The solution for (dy)/(dx)=((x^2y^2))/(1+x) is y=-2/(x^2-2x+2ln(1+x)-3+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((x^2y^2))/(1+x)

\frac{d y}{d x} = \frac{( x ^{2} y ^{2} )}{1 + x}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} y ^{2} )}{1 + x}

Solve separable ODE:

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

\frac{d}{d x} (, x^{2})

\int - x^{\frac{1}{3}} d x

n = 1 \sum \infty \frac{n}{5 ^{n}}

\int 8 x cos (7 x) d x

\int \frac{x ^{4} - 3 x ^{\frac{1}{2}} + 2}{x ^{\frac{3}{2}}} d x

What is the solution for (dy)/(dx)=((x^2y^2))/(1+x) ?
The solution for (dy)/(dx)=((x^2y^2))/(1+x) is y=-2/(x^2-2x+2ln(1+x)-3+c_{1)}