What is the derivative of 2+8x^{3/2} ?

The derivative of 2+8x^{3/2} is 12x^{1/2}

What is the first derivative of 2+8x^{3/2} ?

The first derivative of 2+8x^{3/2} is 12x^{1/2}

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derivative of

2 + 8 x^{\frac{3}{2}}

12 x^{\frac{1}{2}}

Solution steps

\frac{d}{d x} (2 + 8 x^{\frac{3}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (8 x^{\frac{3}{2}})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (8 x^{\frac{3}{2}}) = 12 x^{\frac{1}{2}}

= 0 + 12 x^{\frac{1}{2}}

Simplify

= 12 x^{\frac{1}{2}}

(t^{2} - 2)^{2}

25 y^{^{''}} - 20 y^{^{'}} + 4 y = 0

\int cos (w x) d x

x \frac{d y}{d x} = - 1.5 y

x \to + 0 lim (4 - x)

What is the derivative of 2+8x^{3/2} ?
The derivative of 2+8x^{3/2} is 12x^{1/2}
What is the first derivative of 2+8x^{3/2} ?
The first derivative of 2+8x^{3/2} is 12x^{1/2}