What is (\partial)/(\partial x)(yz+xz+xy) ?

The answer to (\partial)/(\partial x)(yz+xz+xy) is y+z

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(\partial)/(\partial x)(yz+xz+xy)

\frac{\partial}{\partial x} (yz + x z + x y)

y + z

Solution steps

\frac{\partial}{\partial x} (yz + x z + x y)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (yz) + \frac{\partial}{\partial x} (x z) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (x z) = z

\frac{\partial}{\partial x} (x y) = y

= 0 + z + y

Simplify

= y + z

\frac{\partial}{\partial x} (8 \cdot y^{22})

y^{^{''}} - y^{^{'}} = (3 x^{2} + 6 x + 1) e^{x}

x \to + 1 lim (3 x^{3} - 4 x^{2} + x + 9)

y = e^{\frac{x}{2}}

What is (\partial)/(\partial x)(yz+xz+xy) ?
The answer to (\partial)/(\partial x)(yz+xz+xy) is y+z