What is the derivative of x^2a+a^2b+b^2x ?

The derivative of x^2a+a^2b+b^2x is 2ax+b^2

What is the first derivative of x^2a+a^2b+b^2x ?

The first derivative of x^2a+a^2b+b^2x is 2ax+b^2

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\frac{d}{d x} (x^{2} a + a^{2} b + b^{2} x)

2 a x + b^{2}

Solution steps

\frac{d}{d x} (x^{2} a + a^{2} b + b^{2} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} a) + \frac{d}{d x} (a^{2} b) + \frac{d}{d x} (b^{2} x)

\frac{d}{d x} (x^{2} a) = 2 a x

\frac{d}{d x} (a^{2} b) = 0

\frac{d}{d x} (b^{2} x) = b^{2}

= 2 a x + 0 + b^{2}

Simplify

= 2 a x + b^{2}

\int csc^{4} (6 w) d w

\int_{0}^{e} 4 e^{2 x} d x

\int - 2 x + 15 x^{2} - 4 x^{3} + C d x

y^{^{'}} + (\frac{7 x}{x ^{2} + 1}) y = \frac{7 x}{x ^{2} + 1}

\frac{( ( \frac{4}{x} ) ^{2} )}{1 - \frac{4}{x}}

What is the derivative of x^2a+a^2b+b^2x ?
The derivative of x^2a+a^2b+b^2x is 2ax+b^2
What is the first derivative of x^2a+a^2b+b^2x ?
The first derivative of x^2a+a^2b+b^2x is 2ax+b^2