What is the derivative of (((4/x)^2))/(1-4/x) ?

The derivative of (((4/x)^2))/(1-4/x) is (-32x+64)/(x^2(x-4)^2)

What is the first derivative of (((4/x)^2))/(1-4/x) ?

The first derivative of (((4/x)^2))/(1-4/x) is (-32x+64)/(x^2(x-4)^2)

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derivative of

\frac{( ( \frac{4}{x} ) ^{2} )}{1 - \frac{4}{x}}

\frac{- 32 x + 64}{x ^{2} ( x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( \frac{4}{x} ) ^{2}}{1 - \frac{4}{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ( \frac{4}{x} ) ^{2} ) ( 1 - \frac{4}{x} ) - \frac{d}{d x} ( 1 - \frac{4}{x} ) ( \frac{4}{x} ) ^{2}}{( 1 - \frac{4}{x} ) ^{2}}

\frac{d}{d x} ((\frac{4}{x})^{2}) = - \frac{32}{x ^{3}}

\frac{d}{d x} (1 - \frac{4}{x}) = \frac{4}{x ^{2}}

= \frac{( - \frac{32}{x ^{3}} ) ( 1 - \frac{4}{x} ) - \frac{4}{x ^{2}} ( \frac{4}{x} ) ^{2}}{( 1 - \frac{4}{x} ) ^{2}}

Simplify

\frac{( - \frac{32}{x ^{3}} ) ( 1 - \frac{4}{x} ) - \frac{4}{x ^{2}} ( \frac{4}{x} ) ^{2}}{( 1 - \frac{4}{x} ) ^{2}} : \frac{- 32 x + 64}{x ^{2} ( x - 4 ) ^{2}}

= \frac{- 32 x + 64}{x ^{2} ( x - 4 ) ^{2}}

\frac{d}{d x} (4 + 7 x)

\int_{0}^{1} 5^{4 x} d x

\frac{\partial}{\partial x} (y sin (2 x))

x \to 0 + lim (\frac{1}{ln ( x )})

x y y^{^{'}} = 2 y^{2} + 4 x^{2}

What is the derivative of (((4/x)^2))/(1-4/x) ?
The derivative of (((4/x)^2))/(1-4/x) is (-32x+64)/(x^2(x-4)^2)
What is the first derivative of (((4/x)^2))/(1-4/x) ?
The first derivative of (((4/x)^2))/(1-4/x) is (-32x+64)/(x^2(x-4)^2)