What is (\partial)/(\partial x)(e^{xyz-2}) ?

The answer to (\partial)/(\partial x)(e^{xyz-2}) is e^{xyz-2}yz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^{xyz-2})

\frac{\partial}{\partial x} (e^{x yz - 2})

e^{x yz - 2} yz

Solution steps

\frac{\partial}{\partial x} (e^{x yz - 2})

Treat

y, z

as constants

Apply the chain rule:

e^{x yz - 2} \frac{\partial}{\partial x} (x yz - 2)

= e^{x yz - 2} \frac{\partial}{\partial x} (x yz - 2)

\frac{\partial}{\partial x} (x yz - 2) = yz

= e^{x yz - 2} yz

x \to 0 + lim (\frac{2}{x ^{\frac{1}{3}}})

sin^{2} (π x)

\frac{\partial}{\partial x} (98 y^{2} + x^{2} - x^{2} y)

\frac{d}{d x} ((x - 4)^{2} - 5)

n = 0 \sum \infty n e^{- n^{2}}

What is (\partial)/(\partial x)(e^{xyz-2}) ?
The answer to (\partial)/(\partial x)(e^{xyz-2}) is e^{xyz-2}yz