What is the derivative of 2x-2^{-x} ?

The derivative of 2x-2^{-x} is 2+ln(2)*2^{-x}

What is the first derivative of 2x-2^{-x} ?

The first derivative of 2x-2^{-x} is 2+ln(2)*2^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x - 2^{- x})

2 + ln (2) \cdot 2^{- x}

Solution steps

\frac{d}{d x} (2 x - 2^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (2^{- x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2^{- x}) = - ln (2) \cdot 2^{- x}

= 2 - (- ln (2) \cdot 2^{- x})

Simplify

= 2 + ln (2) \cdot 2^{- x}

x \to 2 lim (\frac{x ^{2} - 6}{x - 3})

\frac{d}{d x} (1 + ln^{2} (x))

\frac{\partial}{\partial x} (tan (2 x))

\int_{0}^{1} 2 π x (x - x^{3}) d x

\frac{d}{d x} (2 x^{2} + 2)

What is the derivative of 2x-2^{-x} ?
The derivative of 2x-2^{-x} is 2+ln(2)*2^{-x}
What is the first derivative of 2x-2^{-x} ?
The first derivative of 2x-2^{-x} is 2+ln(2)*2^{-x}