What is the first derivative of 2x^2+2 ?

The first derivative of 2x^2+2 is 4x

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derivative of 2x^2+2

\frac{d}{d x} (2 x^{2} + 2)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d}{d x} (\frac{2 x ^{9} - 5 x + x}{x ^{4}})

\int_{0}^{r} 0 d r

\int \frac{5}{( x - 2 ) ( x ^{2} + 4 )} d x

\int x^{2} I n d x

lo g_{a} (x)